180=6(b)^2

Solution for 180=6(b)^2 equation:

180=6(b)^2

We move all terms to the left:

180-(6(b)^2)=0

determiningTheFunctionDomain
-6b^2+180=0

a = -6; b = 0; c = +180;
Δ = b2-4ac
Δ = 02-4·(-6)·180
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*-6}=\frac{0-12\sqrt{30}}{-12}
=-\frac{12\sqrt{30}}{-12}
=-\frac{\sqrt{30}}{-1}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*-6}=\frac{0+12\sqrt{30}}{-12}
=\frac{12\sqrt{30}}{-12}
=\frac{\sqrt{30}}{-1}
$